Optimal. Leaf size=297 \[ -\frac {\left (-2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )}{4 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (-2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )}{4 \sqrt {2} a^{3/4} c^{5/4}}-\frac {\left (2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{2 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}+1\right )}{2 \sqrt {2} a^{3/4} c^{5/4}}+\frac {e^2 x}{c} \]
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Rubi [A] time = 0.29, antiderivative size = 297, normalized size of antiderivative = 1.00, number of steps used = 11, number of rules used = 7, integrand size = 19, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.368, Rules used = {1171, 1168, 1162, 617, 204, 1165, 628} \[ -\frac {\left (-2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )}{4 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (-2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )}{4 \sqrt {2} a^{3/4} c^{5/4}}-\frac {\left (2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{2 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}+1\right )}{2 \sqrt {2} a^{3/4} c^{5/4}}+\frac {e^2 x}{c} \]
Antiderivative was successfully verified.
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Rule 204
Rule 617
Rule 628
Rule 1162
Rule 1165
Rule 1168
Rule 1171
Rubi steps
\begin {align*} \int \frac {\left (d+e x^2\right )^2}{a+c x^4} \, dx &=\int \left (\frac {e^2}{c}+\frac {c d^2-a e^2+2 c d e x^2}{c \left (a+c x^4\right )}\right ) \, dx\\ &=\frac {e^2 x}{c}+\frac {\int \frac {c d^2-a e^2+2 c d e x^2}{a+c x^4} \, dx}{c}\\ &=\frac {e^2 x}{c}+\frac {\left (c d^2-2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \int \frac {\sqrt {a} \sqrt {c}-c x^2}{a+c x^4} \, dx}{2 \sqrt {a} c^{3/2}}+\frac {\left (c d^2+2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \int \frac {\sqrt {a} \sqrt {c}+c x^2}{a+c x^4} \, dx}{2 \sqrt {a} c^{3/2}}\\ &=\frac {e^2 x}{c}-\frac {\left (c d^2-2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{c}}+2 x}{-\frac {\sqrt {a}}{\sqrt {c}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}-x^2} \, dx}{4 \sqrt {2} a^{3/4} c^{5/4}}-\frac {\left (c d^2-2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \int \frac {\frac {\sqrt {2} \sqrt [4]{a}}{\sqrt [4]{c}}-2 x}{-\frac {\sqrt {a}}{\sqrt {c}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}-x^2} \, dx}{4 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (c d^2+2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \int \frac {1}{\frac {\sqrt {a}}{\sqrt {c}}-\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}+x^2} \, dx}{4 \sqrt {a} c^{3/2}}+\frac {\left (c d^2+2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \int \frac {1}{\frac {\sqrt {a}}{\sqrt {c}}+\frac {\sqrt {2} \sqrt [4]{a} x}{\sqrt [4]{c}}+x^2} \, dx}{4 \sqrt {a} c^{3/2}}\\ &=\frac {e^2 x}{c}-\frac {\left (c d^2-2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{4 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (c d^2-2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{4 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (c d^2+2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{2 \sqrt {2} a^{3/4} c^{5/4}}-\frac {\left (c d^2+2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{2 \sqrt {2} a^{3/4} c^{5/4}}\\ &=\frac {e^2 x}{c}-\frac {\left (c d^2+2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{2 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (c d^2+2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )}{2 \sqrt {2} a^{3/4} c^{5/4}}-\frac {\left (c d^2-2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \log \left (\sqrt {a}-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{4 \sqrt {2} a^{3/4} c^{5/4}}+\frac {\left (c d^2-2 \sqrt {a} \sqrt {c} d e-a e^2\right ) \log \left (\sqrt {a}+\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {c} x^2\right )}{4 \sqrt {2} a^{3/4} c^{5/4}}\\ \end {align*}
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Mathematica [A] time = 0.26, size = 269, normalized size = 0.91 \[ \frac {8 a^{3/4} \sqrt [4]{c} e^2 x+\sqrt {2} \left (2 \sqrt {a} \sqrt {c} d e+a e^2-c d^2\right ) \log \left (-\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )+\sqrt {2} \left (-2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \log \left (\sqrt {2} \sqrt [4]{a} \sqrt [4]{c} x+\sqrt {a}+\sqrt {c} x^2\right )-2 \sqrt {2} \left (2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}\right )+2 \sqrt {2} \left (2 \sqrt {a} \sqrt {c} d e-a e^2+c d^2\right ) \tan ^{-1}\left (\frac {\sqrt {2} \sqrt [4]{c} x}{\sqrt [4]{a}}+1\right )}{8 a^{3/4} c^{5/4}} \]
Antiderivative was successfully verified.
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fricas [B] time = 0.61, size = 1480, normalized size = 4.98 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.18, size = 318, normalized size = 1.07 \[ \frac {x e^{2}}{c} + \frac {\sqrt {2} {\left (\left (a c^{3}\right )^{\frac {1}{4}} c^{2} d^{2} - \left (a c^{3}\right )^{\frac {1}{4}} a c e^{2} + 2 \, \left (a c^{3}\right )^{\frac {3}{4}} d e\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, x + \sqrt {2} \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}}{2 \, \left (\frac {a}{c}\right )^{\frac {1}{4}}}\right )}{4 \, a c^{3}} + \frac {\sqrt {2} {\left (\left (a c^{3}\right )^{\frac {1}{4}} c^{2} d^{2} - \left (a c^{3}\right )^{\frac {1}{4}} a c e^{2} + 2 \, \left (a c^{3}\right )^{\frac {3}{4}} d e\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, x - \sqrt {2} \left (\frac {a}{c}\right )^{\frac {1}{4}}\right )}}{2 \, \left (\frac {a}{c}\right )^{\frac {1}{4}}}\right )}{4 \, a c^{3}} + \frac {\sqrt {2} {\left (\left (a c^{3}\right )^{\frac {1}{4}} c^{2} d^{2} - \left (a c^{3}\right )^{\frac {1}{4}} a c e^{2} - 2 \, \left (a c^{3}\right )^{\frac {3}{4}} d e\right )} \log \left (x^{2} + \sqrt {2} x \left (\frac {a}{c}\right )^{\frac {1}{4}} + \sqrt {\frac {a}{c}}\right )}{8 \, a c^{3}} - \frac {\sqrt {2} {\left (\left (a c^{3}\right )^{\frac {1}{4}} c^{2} d^{2} - \left (a c^{3}\right )^{\frac {1}{4}} a c e^{2} - 2 \, \left (a c^{3}\right )^{\frac {3}{4}} d e\right )} \log \left (x^{2} - \sqrt {2} x \left (\frac {a}{c}\right )^{\frac {1}{4}} + \sqrt {\frac {a}{c}}\right )}{8 \, a c^{3}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.00, size = 412, normalized size = 1.39 \[ \frac {\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, d^{2} \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}-1\right )}{4 a}+\frac {\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, d^{2} \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}+1\right )}{4 a}+\frac {\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, d^{2} \ln \left (\frac {x^{2}+\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, x +\sqrt {\frac {a}{c}}}{x^{2}-\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, x +\sqrt {\frac {a}{c}}}\right )}{8 a}+\frac {\sqrt {2}\, d e \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}-1\right )}{2 \left (\frac {a}{c}\right )^{\frac {1}{4}} c}+\frac {\sqrt {2}\, d e \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}+1\right )}{2 \left (\frac {a}{c}\right )^{\frac {1}{4}} c}+\frac {\sqrt {2}\, d e \ln \left (\frac {x^{2}-\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, x +\sqrt {\frac {a}{c}}}{x^{2}+\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, x +\sqrt {\frac {a}{c}}}\right )}{4 \left (\frac {a}{c}\right )^{\frac {1}{4}} c}+\frac {e^{2} x}{c}-\frac {\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, e^{2} \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}-1\right )}{4 c}-\frac {\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, e^{2} \arctan \left (\frac {\sqrt {2}\, x}{\left (\frac {a}{c}\right )^{\frac {1}{4}}}+1\right )}{4 c}-\frac {\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, e^{2} \ln \left (\frac {x^{2}+\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, x +\sqrt {\frac {a}{c}}}{x^{2}-\left (\frac {a}{c}\right )^{\frac {1}{4}} \sqrt {2}\, x +\sqrt {\frac {a}{c}}}\right )}{8 c} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 2.36, size = 288, normalized size = 0.97 \[ \frac {e^{2} x}{c} + \frac {\frac {2 \, \sqrt {2} {\left (c^{\frac {3}{2}} d^{2} + 2 \, \sqrt {a} c d e - a \sqrt {c} e^{2}\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, \sqrt {c} x + \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {c}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {c}} \sqrt {c}} + \frac {2 \, \sqrt {2} {\left (c^{\frac {3}{2}} d^{2} + 2 \, \sqrt {a} c d e - a \sqrt {c} e^{2}\right )} \arctan \left (\frac {\sqrt {2} {\left (2 \, \sqrt {c} x - \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}}\right )}}{2 \, \sqrt {\sqrt {a} \sqrt {c}}}\right )}{\sqrt {a} \sqrt {\sqrt {a} \sqrt {c}} \sqrt {c}} + \frac {\sqrt {2} {\left (c^{\frac {3}{2}} d^{2} - 2 \, \sqrt {a} c d e - a \sqrt {c} e^{2}\right )} \log \left (\sqrt {c} x^{2} + \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}} x + \sqrt {a}\right )}{a^{\frac {3}{4}} c^{\frac {3}{4}}} - \frac {\sqrt {2} {\left (c^{\frac {3}{2}} d^{2} - 2 \, \sqrt {a} c d e - a \sqrt {c} e^{2}\right )} \log \left (\sqrt {c} x^{2} - \sqrt {2} a^{\frac {1}{4}} c^{\frac {1}{4}} x + \sqrt {a}\right )}{a^{\frac {3}{4}} c^{\frac {3}{4}}}}{8 \, c} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 4.79, size = 1479, normalized size = 4.98 \[ \frac {e^2\,x}{c}-2\,\mathrm {atanh}\left (\frac {8\,c^3\,d^4\,x\,\sqrt {\frac {d\,e^3}{4\,c^2}-\frac {d^3\,e}{4\,a\,c}+\frac {d^4\,\sqrt {-a^3\,c^5}}{16\,a^3\,c^3}+\frac {e^4\,\sqrt {-a^3\,c^5}}{16\,a\,c^5}-\frac {3\,d^2\,e^2\,\sqrt {-a^3\,c^5}}{8\,a^2\,c^4}}}{4\,a^2\,d\,e^5-\frac {2\,d^6\,\sqrt {-a^3\,c^5}}{a^2}+4\,c^2\,d^5\,e+\frac {2\,a\,e^6\,\sqrt {-a^3\,c^5}}{c^3}-24\,a\,c\,d^3\,e^3-\frac {14\,d^2\,e^4\,\sqrt {-a^3\,c^5}}{c^2}+\frac {14\,d^4\,e^2\,\sqrt {-a^3\,c^5}}{a\,c}}+\frac {8\,a^2\,c\,e^4\,x\,\sqrt {\frac {d\,e^3}{4\,c^2}-\frac {d^3\,e}{4\,a\,c}+\frac {d^4\,\sqrt {-a^3\,c^5}}{16\,a^3\,c^3}+\frac {e^4\,\sqrt {-a^3\,c^5}}{16\,a\,c^5}-\frac {3\,d^2\,e^2\,\sqrt {-a^3\,c^5}}{8\,a^2\,c^4}}}{4\,a^2\,d\,e^5-\frac {2\,d^6\,\sqrt {-a^3\,c^5}}{a^2}+4\,c^2\,d^5\,e+\frac {2\,a\,e^6\,\sqrt {-a^3\,c^5}}{c^3}-24\,a\,c\,d^3\,e^3-\frac {14\,d^2\,e^4\,\sqrt {-a^3\,c^5}}{c^2}+\frac {14\,d^4\,e^2\,\sqrt {-a^3\,c^5}}{a\,c}}-\frac {48\,a\,c^2\,d^2\,e^2\,x\,\sqrt {\frac {d\,e^3}{4\,c^2}-\frac {d^3\,e}{4\,a\,c}+\frac {d^4\,\sqrt {-a^3\,c^5}}{16\,a^3\,c^3}+\frac {e^4\,\sqrt {-a^3\,c^5}}{16\,a\,c^5}-\frac {3\,d^2\,e^2\,\sqrt {-a^3\,c^5}}{8\,a^2\,c^4}}}{4\,a^2\,d\,e^5-\frac {2\,d^6\,\sqrt {-a^3\,c^5}}{a^2}+4\,c^2\,d^5\,e+\frac {2\,a\,e^6\,\sqrt {-a^3\,c^5}}{c^3}-24\,a\,c\,d^3\,e^3-\frac {14\,d^2\,e^4\,\sqrt {-a^3\,c^5}}{c^2}+\frac {14\,d^4\,e^2\,\sqrt {-a^3\,c^5}}{a\,c}}\right )\,\sqrt {\frac {a^2\,e^4\,\sqrt {-a^3\,c^5}+c^2\,d^4\,\sqrt {-a^3\,c^5}-4\,a^2\,c^4\,d^3\,e+4\,a^3\,c^3\,d\,e^3-6\,a\,c\,d^2\,e^2\,\sqrt {-a^3\,c^5}}{16\,a^3\,c^5}}-2\,\mathrm {atanh}\left (\frac {8\,c^3\,d^4\,x\,\sqrt {\frac {d\,e^3}{4\,c^2}-\frac {d^3\,e}{4\,a\,c}-\frac {d^4\,\sqrt {-a^3\,c^5}}{16\,a^3\,c^3}-\frac {e^4\,\sqrt {-a^3\,c^5}}{16\,a\,c^5}+\frac {3\,d^2\,e^2\,\sqrt {-a^3\,c^5}}{8\,a^2\,c^4}}}{\frac {2\,d^6\,\sqrt {-a^3\,c^5}}{a^2}+4\,a^2\,d\,e^5+4\,c^2\,d^5\,e-\frac {2\,a\,e^6\,\sqrt {-a^3\,c^5}}{c^3}-24\,a\,c\,d^3\,e^3+\frac {14\,d^2\,e^4\,\sqrt {-a^3\,c^5}}{c^2}-\frac {14\,d^4\,e^2\,\sqrt {-a^3\,c^5}}{a\,c}}+\frac {8\,a^2\,c\,e^4\,x\,\sqrt {\frac {d\,e^3}{4\,c^2}-\frac {d^3\,e}{4\,a\,c}-\frac {d^4\,\sqrt {-a^3\,c^5}}{16\,a^3\,c^3}-\frac {e^4\,\sqrt {-a^3\,c^5}}{16\,a\,c^5}+\frac {3\,d^2\,e^2\,\sqrt {-a^3\,c^5}}{8\,a^2\,c^4}}}{\frac {2\,d^6\,\sqrt {-a^3\,c^5}}{a^2}+4\,a^2\,d\,e^5+4\,c^2\,d^5\,e-\frac {2\,a\,e^6\,\sqrt {-a^3\,c^5}}{c^3}-24\,a\,c\,d^3\,e^3+\frac {14\,d^2\,e^4\,\sqrt {-a^3\,c^5}}{c^2}-\frac {14\,d^4\,e^2\,\sqrt {-a^3\,c^5}}{a\,c}}-\frac {48\,a\,c^2\,d^2\,e^2\,x\,\sqrt {\frac {d\,e^3}{4\,c^2}-\frac {d^3\,e}{4\,a\,c}-\frac {d^4\,\sqrt {-a^3\,c^5}}{16\,a^3\,c^3}-\frac {e^4\,\sqrt {-a^3\,c^5}}{16\,a\,c^5}+\frac {3\,d^2\,e^2\,\sqrt {-a^3\,c^5}}{8\,a^2\,c^4}}}{\frac {2\,d^6\,\sqrt {-a^3\,c^5}}{a^2}+4\,a^2\,d\,e^5+4\,c^2\,d^5\,e-\frac {2\,a\,e^6\,\sqrt {-a^3\,c^5}}{c^3}-24\,a\,c\,d^3\,e^3+\frac {14\,d^2\,e^4\,\sqrt {-a^3\,c^5}}{c^2}-\frac {14\,d^4\,e^2\,\sqrt {-a^3\,c^5}}{a\,c}}\right )\,\sqrt {-\frac {a^2\,e^4\,\sqrt {-a^3\,c^5}+c^2\,d^4\,\sqrt {-a^3\,c^5}+4\,a^2\,c^4\,d^3\,e-4\,a^3\,c^3\,d\,e^3-6\,a\,c\,d^2\,e^2\,\sqrt {-a^3\,c^5}}{16\,a^3\,c^5}} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 1.48, size = 238, normalized size = 0.80 \[ \operatorname {RootSum} {\left (256 t^{4} a^{3} c^{5} + t^{2} \left (- 128 a^{3} c^{3} d e^{3} + 128 a^{2} c^{4} d^{3} e\right ) + a^{4} e^{8} + 4 a^{3} c d^{2} e^{6} + 6 a^{2} c^{2} d^{4} e^{4} + 4 a c^{3} d^{6} e^{2} + c^{4} d^{8}, \left (t \mapsto t \log {\left (x + \frac {- 128 t^{3} a^{3} c^{4} d e - 4 t a^{4} c e^{6} + 60 t a^{3} c^{2} d^{2} e^{4} - 60 t a^{2} c^{3} d^{4} e^{2} + 4 t a c^{4} d^{6}}{a^{4} e^{8} - 4 a^{3} c d^{2} e^{6} - 10 a^{2} c^{2} d^{4} e^{4} - 4 a c^{3} d^{6} e^{2} + c^{4} d^{8}} \right )} \right )\right )} + \frac {e^{2} x}{c} \]
Verification of antiderivative is not currently implemented for this CAS.
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